A^-b is the same as 1/a^b.

When there is a negative power, place the number and power over 1.

a^b/a^c = a^(b-c).

c is a negative power, because it is being divided, and is underneath b, which is a positive (and so it stays in the numerator).

a^c/b^c = (a/b)^c

Inside this one, the power of c is distributed to all numbers inside the parenthesis, in this case a and b.

hope this helps

3 0

3 years ago

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What's the answer she gave the class a test and I dont know the answer cause she ain't teach us

shtirl [24]

I agree with what they said

3 0

3 years ago

Solve the two-step equation. 5.1 = –3x – 4.2 1. Add 4.2 to both sides. 2. Divide both sides by -3. The solution is x = _________

Serggg [28]

Answer:

5.1 = -3x - 4.2

-3x - 4.2 = 5.1

-3x = 5.1 + 4.2

-3x = 9.3

x = 9.3/-3

x = -3.1

6 0

3 years ago

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(3 marks) A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year. The battery live

Ksenya-84 [330]

Answer:

0.8041 = 80.41% probability that a given battery will last between 2.3 and 3.6 years

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A certain type of storage battery lasts, on average, 3.0 years with a standard deviation of 0.5 year

This means that $\mu = 3, \sigma = 0.5$