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Schach [20]
3 years ago
14

Tomas got 3/4 of the questions correct on an exam. There were 24 questions on the exam. What number of questions did Tomas get c

orrect?
Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

18 questions

Step-by-step explanation:

In order to get the answer you have to multiply 3/4 by 24.

(3/4)(24) = 18

Therefore, Tomas got 18 questions correct.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

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Answer:

Hi, I believe 1-0.25c is the correct answer.

Step-by-step explanation:

This is because 25% off would mean taking 25 off of a whole amount, which in this case would be one.

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What is the value of x? inscribed angles
Flura [38]

The value of x is 84°.

Solution:

Measure of intercepted arc = 168°

Measure of angle x = ?

<u>Tangent-chord relationship:</u>

<em>If a tangent and a chord intersect at a point, then the measure of each angle formed is half of the measure of its intercepted arc.</em>

$\Rightarrow \angle x = \frac{1}{2}\times 168^\circ

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3 years ago
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Bogdan [553]
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3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

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Answer:

y= \sqrt{x}

Step-by-step explanation:

To find inverse of something, just switch the variables

x=y^2

now try to solve back in terms of y

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