Answer:(-22)
Step-by-step explanation:
What is the value of h (-2) when h (3) = 32 +1?
hx3=33
33 divided by 3
which means h=11
that makes 11(-2)
=(-22)
Answer: 40x+18
Step-by-step explanation:
Answer:
There will be 10 teams and 8 children left over.
Step-by-step explanation:
12 * 10 = 120. This is the closest you can get to 128 without going over, so that means there will be 10 teams of 12 children. 128 - 120 = 8. Therefore, there are 8 children left over.
Answer:
Using z score formula:
X = z ∂ + µ
= 157.833
Step-by-step explanation:
Solution:
Mean = µ = 1262
Standard deviation = ∂ = 117
(a) 28th percentile for the number of chocolate chip.
P( z < z) = 28%
= 0.28
P( z<- 0.58) = 0.28
Z = -0.58
By using z score formula:
Z = x - µ /∂
-0.58= x – 117 / 1262
X = (- 0.58)(117) + (1262)
= 1194.14
(b) Middle 97% of bag.
P(-z < z < z) = 97%
= 0.97
P( z < z) – p(z < -z) = 0.97
2p(z < z) -1 = 0.97
2p (z < z) = 1 + 0.97
P(z < z) = 1.97 / 2
= 0.99
P(z < 2.33) = 0.99
Z ± 2.33
By using z score formula:
Z = x - µ / ∂
X = z ∂ + µ
= - 2.33 x 117 + 1262
=989.39
Z = 2.33
X = z ∂ + µ
= 2.33 x 117 + 1262
=1533.61
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.
By using standard normal table,
The z dist’n formula:
P(z < z ) = 25%
=0.25
P(z < -0.6745) = 0.25
Z = 0.6745
Using z score formula:
X = z∂ + µ
= - 0.6745 x 117 + 1262
= 1183.0835
First quartile = Q1 =1183.0835
The third quartile is:
P(z<z) = 75%
= 0.75
P(z < 0.6745) = 0.75
Z = 0.6745
Using z score formula:
X = z ∂ + µ
= 0.6745 x 117 + 1262
= 1340.9165
IQR = Q3 – Q1
= 1340.9165 – 1183.0835
= 157.833
2/3 (3x + 9) = -2(2x + 6)
Step by step
2/3 * 3x and 2/3 * 9 = 2x and 6
which is 2x + 6 (since 6 is a positive put a plus 6 [ + 6 ] )
-2 * 2x and -2 * 6 = -4x and -12
which is -4x - 12 (since 12 is negative put a minus 12 [ - 12 ])
We now have 2x + 6 = -4x - 12
now add 4x on both sides
2x + 6 + 4x = −4x − 12 + 4x
6x + 6 = −12
now Subtract 6 from both sides.
6x + 6 − 6 = −12−6
6x=−18
finally Divide both sides by 6.
6x/6 = -18/6
x = -3
The answer is x=−3
