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Dahasolnce [82]
2 years ago
15

10 points !! Which expression is equivalent to this polynomial x^2+12

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Answer:

x2+12 (except the 2 in small)

Step-by-step explanation:

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1. I am a multiple of 2, 4, and 8. The sum of my two digits is 7. Who am i?
vaieri [72.5K]

Answer:

a. 16

b. 26

c. (11,13) and (17,19)

d. 3,8,12

Step-by-step explanation:

1. 2x8 = 16, sum of 1 +6 ( 2 digits)= 7

2. 2+3+5+7+11= 28

3. 10 to 20 ( 11,13,17,19) so we can make a pair that has difference of 2 like (11,13)

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Why is the equation y = 5x - 10 not proportional?
Kryger [21]

Answer:

x=2

Step-by-step explanation:

to find x- intercept substitute y=0

move variable to the left hand side and change its sign -5x=-10

then divide both sides of the equation by -5

and the final answer is x=2

hope this helps!

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3 years ago
Melissa asked 10 students how many courses they have taken so far at her college. Here is the list of answers.
almond37 [142]

Answer:

Step-by-step explanation:

The question has asked who has taken fewer than 15 courses

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2 years ago
Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti
Vikki [24]

Answer:

General Solution is y=x^{3}+cx^{2} and the particular solution is  y=x^{3}-\frac{1}{2}x^{2}

Step-by-step explanation:

x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}

This is a linear diffrential equation of type

\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)..................(i)

here p(x)=\frac{-2}{x}

q(x)=x^{2}

The solution of equation i is given by

y\times e^{\int p(x)dx}=\int  e^{\int p(x)dx}\times q(x)dx

we have e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}

Thus the solution becomes

\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+cy=x^{3}+cx^{2

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have 6=8+4c

Thus solving for c we get c = -1/2

Thus particular solution becomes

y=x^{3}-\frac{1}{2}x^{2}

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3 years ago
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