X^1/2 - x
-2x^3 - x^1/2 - x
-2x^3 - 2x
i think this is it
Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
For number one the answer is A 2,880
for number two the answer is C 75% <--- i guessed
hope this helped
Answer:
Step-by-step explanation:
x²+2 ×x×5+5²=-20x+2×x×5-3
(x+5)²=-20+10x-3
(x+5)²=-10x-3
A)
is false. There is no solution.
B)
is false. There is no solution.
C)
is
true. It has infinite solutions.
D)
is
true. It has infinite solutions.
E)
is false. There is no solution.
