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3 years ago

What is the slope of the line that passes through the points (1, -3) and (4, 2)?

Mathematics

1 answer:

Vitek1552 [10]3 years ago

6 0

in this situation it would be the last one or d.

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Counting back from 5 what number follow 4

qwelly [4]

Answer:

5 4 3 2 1

Step-by-step explanation:

is this what ur asking

5 0

3 years ago

Read 2 more answers

A kite flying in the air has an 7-ft line attached to it. Its line is pulled taut and casts a 5-ft shadow find the heights of th

Stels [109]

The height of the kite is 4.89 feet

Explanation

The length of the line attached to the kite=7 feet

The length of the shadow that is cast on the ground=5 feet

the system forms a right angled triangle where the taught string of the kite is the hypotenuse, the shadow is the base and the height of the kite above the ground is the height.

H=7 feet

b=5 feet

using pythagoras theorem

$h^2+b^2=H^2\\h^2=H^2-b^2\\h^2=7^2-5^2\\=49-25\\=24\\h=\sqrt{24\\} =2\sqrt{6} \\=4.89 feet$

The kite is 4.89 feet above the ground

3 0

2 years ago

What is the length of side AB of parallelogram ABCD? units 4g - 8 B q+4

Andrews [41]

Answer:

8 units

Step-by-step explanation:

» Concepts

Parallelogram Side Theorem states that the opposite sides of a parallelogram are congruent, meaning they have the same length.

» Application

In this case, we're asked to apply the theorem to find the value of q and then find the length of AB. Thus, we have to set up the equation 4q - 8 = q + 4.

» Solving

Step 1: Subtract q from both sides.

$4q-8-q=q+4-q$
$3q-8=4$

Step 2: Add 8 to both sides.

$3q-8+8=4+8$
$3q=12$

Step 3: Divide both sides by 3.

$3q/3 = 12/3$
$q=4$

Step 4: Plug in the value of q for side AB.

$4(4)-8$
$16-8$
$8$

Therefore, the answer is 8 units.

6 0

2 years ago

Mike has $600 in his bank account over the last five years the amount in his account has went down to $250 what integer represen

UkoKoshka [18]

600 ---> 250

600 - 250 = 350

350 / 5 = 70

Average decrease in value per year: $70

7 0

3 years ago

A particular circle in the standard (x,y) coordinate

matrenka [14]

For any circle with Cartesian equation
$(x-a)^2 + (y-b)^2 = r^2$ ,
we have that the centre of the circle is $(a,b)$ , and the radius of the circle is $r$ .

So in the case that
$(x-5)^2 + y^2 = 38$ ,
we essentially have that
$a = 5, b = 0, r^2 = 38$ .

So the centre of the circle is $(5,0)$ , and the radius is $\sqrt{38}$ .

7 0

3 years ago