Answer:
a=6, b=-12, and c=0
Step-by-step explanation:
The standard format for the quadratic formula is ax^2+bx+c (=0).
If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.
6x^2=12x We can move over the 12x to the other side.
6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0
6x^2-12x+0=0
So a=6, b=-12, and c=0
Answer:

<em><u>I </u></em><em><u>hope </u></em><em><u>it </u></em><em><u>helps</u></em>
<em><u>have </u></em><em><u>a </u></em><em><u>great </u></em><em><u>day </u></em>
<em><u>
</u></em>
For this case, the first thing we must do is define variables:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:

their difference is 1.6:

Solving the system we have:
We add both equations:

Then, we look for the value of y using any of the equations:
Answer:
The numbers are:
Answer:
12 bags
Step-by-step explanation:
9×8=72 beads all together
72/6=12 bags of beads