If x=3 and y=5 then you just substitute.
6(5)/3
30/3
=10
10 is your answer.
Answer:
<em>Answer is </em><em>10</em><em>/</em><em>7</em>
Step-by-step explanation:
[tex] (\frac{6}{10} )r = \frac{6}{7} \\ cancelling \: 6 \: on \: both \: sides \\ (\frac{1}{10} )r = \frac{1}{7} \\ \frac{r}{10} = \frac{1}{7} \\ r = \frac{10}{7} \: \\
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not possible because the area of a square is always a square of it's length and a square cannot be a prime number
<span>The expression of the square root of 19x must be simplified when x is equal to 28. This is because possible factors of 28 can be seen to be 4 and 7, and 4 is a perfect square. This means it can be pulled outside of the square root when evaluated. The other options include only prime factors that could not be pulled out. (3,5), (3,7), (1,41)
28 simplifies as such:
Sqrt(19*28) = Sqrt(19*4*7) = 2*Sqrt(19*7) = 2*Sqrt(133).</span>
