Answer:
he has 300 nickels
Step-by-step explanation:
Answer: 24 possible ways
A set of 4 tires can be fixed in any of the four possible positions in a car as it is mentioned that all four tires are interchangeable. Therefore, the 4 tires can be fixed in 4! ways. The four interchangeable tires can be put on a car in 24 possible ways.
Step-by-step explanation:
looked it up
Step-by-step explanation:
<u>Given coordinates of the rectangle ABCD:</u>
- A(0, 0), B(a, 0), C(x, y), D(0, b)
Lets first find coordinates of C
We can see that A and B are on same line horizontally, so C and D will be on the parallel line
The distance AB and CD are equal also distance AD and BC are equal, therefore
- AB = a - 0 = a, CD = a
- AD = b - 0 = b, BC = b
<u>So the coordinates of C are:</u>
<u>Now the diagonals:</u>
- AC = √(a-0)² + (b-0)² = √a²+b²
- BD =√(0-a)² + (b -0)² = √a² + b²
Since AC = BD, we can state they are congruent
Answer:
The fourth pair of statement is true.
9∈A, and 9∈B.
Step-by-step explanation:
Given that,
U={x| x is real number}
A={x| x∈ U and x+2>10}
B={x| x∈ U and 2x>10}
If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.
Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.
So, 5∉A, and 5∉B.
If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.
Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.
So, 6∉A, and 6∈B.
If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.
Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.
So, 8∉A, and 8∈B.
If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.
Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.
So, 9∈A, and 9∈B.
Answer:
your answer is c
Step-by-step explanation:
In the fraction Jonah made split his table into 10 parts to show 3/5 and to get the 10 parts he multiplied 5 by 2 to get 10 and you have to do the same to the 3 so 3 multiplied by 2 is 6
