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ahrayia [7]
3 years ago
12

Samantha uses 3 cups of flour to

Mathematics
2 answers:
navik [9.2K]3 years ago
5 0

Answer:

25 cupcakes

Step-by-step explanation:

set up a proportion then cross-multiply:

3/15 = 5/c

3c = 75

c = 25

Anna007 [38]3 years ago
5 0

Answer:

25 cupcakes

Step-by-step explanation:

1. What is the ratio?

3 cups of flour to 15 cupcakes (3:15)

2. Quotient

What is the quotient of 15 and 3? 5

3. 5 x 5

25

Answer: 25 cupcakes

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What is the area of this figure?
alina1380 [7]

Answer:

48??

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Select the correct answer.
Stella [2.4K]

Answer:

Step-by-step explanation:

Y=25{1/2) x

6 0
3 years ago
Read 2 more answers
3. If mZEFH = (5x + 1), mZHFG = 62°, and<br> mZEFG = (18x + 11), find each measure.
arsen [322]

Answer/Step-by-step explanation:

Given:

m<EFH = (5x + 1)°

m<HFG = 62°

m<EFG = (18x + 11)°

Required:

1. Value of x

2. m<EFH

3. m<EFG

SOLUTION:

1. Value of x

m<EFH + m<HFG = m<EFG (angle addition postulate)

(5x + 1) + 62 = (18x + 11)

Solve for x using this equation

5x + 1 + 62 = 18x + 11

5x + 63 = 18x + 11

Subtract 18x from both sides

5x + 63 - 18x = 18x + 11 - 18x

-13x + 63 = 11

Subtract 63 from both sides

-13x + 63 - 63 = 11 - 63

-13x = -52

Divide both sides by -13

-13x/-13 = -52/-13

x = 4

2. m<EFH = 5x + 1

Plug in the value of x

m<EFH = 5(4) + 1 = 20 + 1 = 21°

3. m<EFG = 18x + 11

m<EFG = 18(4) + 11 = 72 + 11 = 83°

8 0
3 years ago
2. Cement has a density of 3.0 g/cm3. You must pour a cement walkway with the
Anon25 [30]

For this case we have to by definition:

d = \frac {M} {V}

Where:

d: It is the density

M: It's the mass

V: It is the volume

According to the data we have to:

d = 3.0 \frac {g} {cm ^ 3}

On the other hand we have that 1 meter is equivalent to 100 centimeters. Thus the measurements of the walkway are:

600 cm long, 100 cm wide and 10 cm thick. Looking for the volume we have:

V = 600 * 100 * 10\\V = 600,000 cm ^ 3

According to the formula we have:

M = d * V\\M = 3.0 \frac {g} {cm ^ 3} * 600,000 cm ^ 3\\M = 1,800,000g

Thus, the mass of the walkway is 1,800,000g

Answer:

1,800,000g

7 0
4 years ago
Your friend claims that it is possible to draw a right triangle where the cosine of either angle (theta) is exactly the same val
avanturin [10]

Answer:

B. No

Cos \ \theta\neq Cos (90-\theta)\textdegree

Step-by-step explanation:

-A right angle triangle has two complimentary acute angles and one right angle.

-\theta is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.

-Complimentary angles add up to 90º.

#For complimentary angles:

Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree

The two acute angles cannot have the same Cosine value.

Hence, she's not correct.

5 0
3 years ago
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