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3 years ago

Calculate the value of b.(b-15)3b°(2b + 45°Diagram not drawn accurately

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

Answer:

b = 30

Step-by-step explanation:

The sum of the 2 angles above the line will equal the angle below the line

3b + b - 15 = 2b + 45

4b - 15 = 2b + 45 ( subtract 2b from both sides )

2b - 15 = 45 ( add 15 to both sides )

2b = 60 ( divide both sides by 2 )

b = 30

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Kevin bought 15 bananas for 4.50. How much does 1 banana cost?

aksik [14]

Answer:

$0.30

Step-by-step explanation:

Divide 4.50 by 15.

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3 years ago

Rowena is proving that AD ≅ EB. Which statement does the ♣ represent in her proof?

zepelin [54]

Using the ASA congruence theorem, the missing statement in her proof is: A. ΔACD ≅ ΔECB.

<h3>What is the ASA Congruence Theorem?</h3>

Two triangles are congruent by the ASA congruence theorem if they have two pairs of corresponding congruent angles and a pair of included congruent sides.

In the proof given in the diagram, using the ASA congruence theorem, Rowena has been able to prove that ΔACD and ΔECB have two pairs of corresponding congruent angles and a pair of included congruent sides.

Therefore, the missing statement in her proof is: A. ΔACD ≅ ΔECB.

Learn more about the ASA congruence theorem on:

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2 years ago

What number is 100% of 113. Help me please

Georgia [21]

100% is always the full number so 113 is your answer

Hope this helps and have a blessed day

8 0

3 years ago

Read 2 more answers

Jenny runs a daycare center and charges $60 per day for each child. There are currently 50 children enrolled at the daycare. At

Brrunno [24]

The answer is B) <span>(60 - 4x)(50 + 2x) = 2,800

The revenue without any change in price is:
$60/student x 50 students = 3,000
Every price drop reduces the price/student by four, so the first term, which describes the fee per student, is 60 - 4x
Every price drop also increases the number of students by two, so the second term, which describes the number of students, is 50 + 2x</span>

4 0

3 years ago

Read 2 more answers

In general, the eigenvalues of an upper triangular matrix are given by the entries on the diagonal. The same is true for a lower

SCORPION-xisa [38]

Answer:

Verified!

Step-by-step explanation:

Upper or lower triangular matrix does not make any difference in finding eigenvalues because equalizing determinant to zero will lead to the same result.

Let's apply it for 2x2 matix:

$A = \left[\begin{array}{ccc}a&0\\b&c\end{array}\right]\\\\\lambda I - A = \left[\begin{array}{ccc}\lambda&0\\0&\lambda\end{array}\right]-\left[\begin{array}{ccc}a&0\\b&c\end{array}\right]\\\\det(\lambda I - A) = det\left[\begin{array}{ccc}\lambda-a&0\\-b&\lambda-c\end{array}\right]=(\lambda-a)(\lambda-c)=0$

So, eigenvalues are entries on the diagonal because zeros in upper side or lower side vanishes the remaining part and only we have $(\lambda-a)(\lambda-c)$ .

So, eigenvalues are $\lambda_1=a,\:\lambda_2=c$

Let's apply it for 3x3 matrix:

$A = \left[\begin{array}{ccc}a&0&0\\b&c&0\\d&e&f\end{array}\right]\\\\\lambda I - A = \left[\begin{array}{ccc}\lambda&0&0\\0&\lambda&0\\0&0&\lambda\end{array}\right]-\left[\begin{array}{ccc}a&0&0\\b&c&0\\d&e&f\end{array}\right]\\\\det(\lambda I - A) = det\left[\begin{array}{ccc}\lambda-a&0&0\\-b&\lambda-c&0\\-d&-e&\lambda-f\end{array}\right]=(\lambda-a)(\lambda-c)(\lambda-f)=0$

So as above, eigenvalues are entries on the diagonal because zeros in upper side or lower side vanishes the remaining part and only we have $(\lambda-a)(\lambda-c)(\lambda-f)$ .

So eigenvalues are $\lambda_1=a,\:\lambda_2=c,\:\lambda_3=f$

4 0

4 years ago

Calculate the value of b.(b-15)3b°(2b + 45°Diagram not drawn accurately​

Calculate the value of b.(b-15)3b°(2b + 45°Diagram not drawn accurately