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marin [14]
3 years ago
12

What is the domain of the function f(x) = x^2-9/x-3 in set notation and in interval notation?

Mathematics
1 answer:
nataly862011 [7]3 years ago
8 0

Answer:

the domain is f[x]=x2x5ty57ju68jujokm000oikukoii

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How do I find the y value for point I such that DI and EI form a 3:5 ratio.
liraira [26]
3:5 ratio mean there are 8 "parts" (3 + 5 = 8)

The distance between the x-coordinates is |-3 - 5| = 8.
So each "part" is 8/8 = 1 unit long in the x-direction. 
You want I to be 3(1) = 3 units from D, so the x-coordinate of I is -3 + 3 = 0.

Same deal for y.
|2 - 5| = 3 is the distance between D and E
Each part is 3/8.
3(3/8) = 9/8
2 + 9/8 = 25/8

So the point I is (0, 25/8)


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3 years ago
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In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9
creativ13 [48]
So...we can write eqn as

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4 0
3 years ago
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The function below models the voltage, in volts, of a certain alternating current after x seconds, where A and b are positive co
Katarina [22]

First of all, we can just ignore A, it has no effect but to vertically stretch our cosine.

If it was only f(x)=cosx, the function would be invertible as long as it's confined between 0 and \pi. Now, the argument of our cosine is not x but bx. It means that it won't stop at \pi, but at \frac{\pi}{b}.

Another way to think about it, "what should i replace x with so I get \pi inside the cosine?"

4 0
3 years ago
Ali simplifies the expression 9y+y to 9y2. why is she wrong?
Scorpion4ik [409]
<span>9y+y = y(9 + 1) = 10y
answer is 10y

if </span><span>9y^2 then it should be 9y times y = 9y^2

hope it helps</span>
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I think it is 33, according to the scale. 1:33 means one cubic inch of the model represents 33 cubic inches of the actual tractor. Agree?
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