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3 years ago

Could ΔABC be congruent to ΔADC by SSS? Explain.

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

Answer:

Step-by-step explanation:

I JUST TOOK THE TEST!!!!!

Vera_Pavlovna [14]3 years ago

6 0

There are 5 ways to test if two figures are congruent, namely;
side-angle-side(SAS)
Angle-side-angle (ASA)
Angle-angle-side(AAS)
Hypotenuse-leg (HL)
3 Sides (SSS)
here we shall focus on SSS. When the three corresponding sides of 2 figures say a triangle have the same length we will conclude that the triangles are congruent by SSS.
Therefore from our choices we can conclude that triangles ABC and ADC are only congruent if the two other side have the same length and BC=DC.

The answer is yes;
B] Yes, but only if BC=DC

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mixer [17]

P(Jonas getting orange) =5/13 =0.385 or 28.5%

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3 years ago

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Nady [450]

Answer:

VW=6

Step-by-step explanation:

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3 years ago

How to factorize -3pa-9b-18pc

Fed [463]

-3pa - 9b - 18pc

For starters, you know that you can't take away any of the letters from the equation because none of the three have the exact same letter; however, they all have something they can be divided by and that is -3.

It would be -3 instead of just 3 because the equation itself starts with a negative. (you could probably do it anyways with just 3, but you'd end up taking out a negative one, anyways, so what's the point?)

Now, you would have: -3 ( pa + 3b + 6pc )

That is truly all you can take out. So, that would end up being your answer since all you can really do is simplify.

7 0

4 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²

AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}$

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting coordinates A and C we get

$l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit$

Similarly for BD we have,

$l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit$

Now Substituting AC and BD in Formula we get

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD$

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}$

Therefore the Area of Rhombus ABCD is 36 unit².

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3 years ago

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ANTONII [103]

Answer:

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