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2 years ago

Could ΔABC be congruent to ΔADC by SSS? Explain.

Mathematics

2 answers:

Kazeer [188]2 years ago

8 0

Answer:

B.

Step-by-step explanation:

I JUST TOOK THE TEST!!!!!

Vera_Pavlovna [14]2 years ago

6 0

There are 5 ways to test if two figures are congruent, namely;
side-angle-side(SAS)
Angle-side-angle (ASA)
Angle-angle-side(AAS)
Hypotenuse-leg (HL)
3 Sides (SSS)
here we shall focus on SSS. When the three corresponding sides of 2 figures say a triangle have the same length we will conclude that the triangles are congruent by SSS.
Therefore from our choices we can conclude that triangles ABC and ADC are only congruent if the two other side have the same length and BC=DC.

The answer is yes;
B] Yes, but only if BC=DC

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Chris

Rainbow [258]

Answer:

meat = $2.40

vegetables = $ 2.40

fruit = $2.40 + X

= 2.40 ÷ 2

= 1.2

therefore 2.40 + 1.2

=$3.6 (For fruits )

= $3.6 + $2.40 + $2.40

= $ 8.4

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7 0

2 years ago

Which one of the following is always true?a. The coefficient of variation measures variability in a positively skewed data set r

Tom [10]

Answer:

C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale

Step-by-step explanation:

Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:

$CV = \frac{\sigma_{x} }{\mu_{x} } * 100%$

Where $\sigma{x}$ is the Standard Deviation

and $\mu_{x}$ is the sample mean

From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.

Coefficient of variation can be used to compare positive as well as negative data on the ratio and interval scale, it is not only used for positive data.

The Interquartile Range is not a measure of central tendency, it is a measure of dispersion.

3 0

3 years ago

Maxine and Sammie have to also mow their parking strips that are the

Lemur [1.5K]

I believe the answer is 3 minutes

At the 3 minute mark, Maxine will be half way done and Sammie will still have 6 minutes left to mow the grass

5 0

3 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$