Step-by-step explanation:
s1 = 300
s2 = s1 × 2 = 300 × 2 = 600
s3 = s2 × 2 = s1 × 2² = 1200
sn = sn-1 × 2 = s1 × 2^(n-1)
s7 = 300 × 2⁶ = 300 × 64 = 19,200
40º
7) In this problem, we can see that both tangent lines to that circle come from the same point O.
So, we can write out the following considering that there is one secant line DO and one tangent line to the circle AO

Short answer: 2 * sqrt(13)
Remark
There are a number of ways to look at this. I'll pick the easiest.
Step one
Factor 52 until there are no more prime factors to be used.
52 = 2 * 26
52 = 2 * 2 * 13. That's as far as you can go.
Rule
For every 2 equal prime factors, 1 of them can be taken out side of the root sign. The other one disappears.
sqrt(52) = sqrt(2*2* 13) = 2*sqrt(13)
Answer 2sqrt(13) <<<< answer
Answer:
The old fish tank hold <u>18.84 cubic feet</u> of water.
Step-by-step explanation:
Given:
An old fish tank in the form of a circular cylinder and it is 2 feet in diameter and 6 feet tall.
Now, to find the cubic feet of water the fish tank hold.
Dimensions of old fish tank are:
<em>Diameter is 2 feet so. we find the radius first.</em>
Radius (
) = 
Height (
) = 
Now, to get the cubic feet off water the tank hold we put formula:
<u><em>(Taking the value of π as 3.14.)</em></u>

Therefore, the old fish tank hold 18.84 cubic feet of water.
You gave us the speed and the frequency, and you need the wavelength.
You were also nice enough to remind us that (fqy)x(lng) = speed.
So . . . F x W = 343 m/s
Divide each side by F :
W = (343 m/s) / F
W = (343 m/s) / (240 / s)
W = (343/240) m
<em>W = 1.429 meters</em>