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gavmur [86]
3 years ago
8

What is 1/4 of 20? what is an equivalent fraction to 1/2?

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0
1/4 of 20 is 5.. and 5/10, 3/6, 2/4, 6/12 are all equal to 1/2
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Find the value of x please help I give brainly<br> 20 points
fiasKO [112]

Answer:

x=148

Step-by-step explanation:

First, find the missing angle by subtracting 100+48 from 180 (all of the angles in a triangle add up to 180). Then, subtract that from 180 (the angles are a linear pair, so they are supplementry, so they add up to 180) x+32=180.

x=148.

(お役に立てれば!)

7 0
3 years ago
Whats the answer for this problem 8x+y=-16 <br> -3x+y=-5
marissa [1.9K]
<span><span> {x,y} = {-7/4,-2}</span> 

Explanation:
</span>System of Linear Equations entered :
 [1] 8x+y=-16
 [2] -3+y=-5

Equations Simplified or Rearranged :<span><span> 
  [1] 8x + y = -16 </span><span> 
  [2] y = -2

Regards
Sonny
</span></span><span>
</span>
8 0
3 years ago
Help me please if you can
makvit [3.9K]

Answer:

-2

Step-by-step explanation:

Add them up: -14

Divide by how many there are: -14 / 7 = -2

4 0
3 years ago
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
Please help its pretty easy
aleksandrvk [35]

Answer:

26/36 numbers are greater than 10

Simplify

13/18

Multiply by the chance of getting tails

13/18 x 1/2 = 13/36

13/36 your answer

26 wanted numbers / 36 amount of numbers

1 tails / 2 sides

Step-by-step explanation:

5 0
3 years ago
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