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erastova [34]
3 years ago
12

Last Week, Carlie had several rice cakes and 3 granola bars as snacks. The snacks contained a total of 800 calories and each ric

e cake had 40 calories, how many rice cakes did she have
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

Step-by-step explanation: how am I supposed to answer this question too hard pass bye.

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Okie. i get it. you guys must like sports a lot 
4 0
3 years ago
I need help on this question can some help
guapka [62]

Answer:There’s a that you can download with a ton of edginuity answers if you type down edginuity answers and hit the pdf by reservamesa and you can find some.

Step-by-step explanation:

5 0
3 years ago
Let X be the number of Heads in 10 fair coin tosses. (a) Find the conditional PMF of X, given that the first two tosses both lan
inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}

                         = \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \  \ \\\\

                                                                                                       k= 2,3..........10For option B:

P(X=k | X \geq 2 ) =  \sum^{10}_{i=2}  \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}

                                                                                                k= 2,3, 4.........10

8 0
3 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Which function represents by the table
andreev551 [17]
F(x)= 4x this is because everything is times 4
3 0
2 years ago
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