Answer: Does not exist.
Step-by-step explanation:
Since, given function, f(x) = 6x tan x, where −π/2 < x < π/2.
⇒ f(x) = 
And, for vertical asymptote, cosx= 0
⇒ x = π/2 + nπ where n is any integer.
But, for any n x is does not exist in the interval ( -π/2, π/2)
Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.
Answer:
7
Step-by-step explanation:
26. y= -7/3+ 0 or just y= -7/3
27. y= -10
Answer:
{1, 0, 16}
Step-by-step explanation:
given..
j(x) = x^2-2x+1
put all given values of domain (1,0 and 5 ) in the equation..
the values you get are range of the function