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Snezhnost [94]
3 years ago
11

What tool is used to draw circles

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

Pair of compasses.

Step-by-step explanation:

These are used to inscribe circles/arcs.

Compasses are used in maths, navigation,e.t.c.

Hope it helps.

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Trigonometry and trigonometric functions
zaharov [31]

Answer:

The trigonometric functions include the following 6 functions: sine, cosine, tangent, cotangent, secant, and cosecant. For each of these functions, there is an inverse trigonometric function. The trigonometric functions can be defined using the unit circle.

Step-by-step explanation:

6 0
3 years ago
The table above represents what type of function?
exis [7]

Answer:

A?? because I think it's not linear because it's not proportional

7 0
3 years ago
Read 2 more answers
If the store paid $75 for a clarent and sold it for 100
IceJOKER [234]

Answer:

Is this the full question?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is 3.57 as a fraction
Ainat [17]
357/100
because .57 is the same as 57 hundriths which translates to 57/100. Now you have 3 and 57/100 and to make thing into an improper fraction you follow these steps.
1. mulitply the whole number (the number in front on the fraction) by the denominator (the lower part of the fraction). In our case, multiply 3 and 100. You get 300.
2. Add your answer to the numorator (the upper part on the fraction). 300 plus 57 equals 357.
3. Use your answer as the new numorator and keep the original denomanator.
Answer: 357/100
3 0
3 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
3 years ago
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