In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
x ≈ 14.87
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )
x = 
≈ 14.87 ( to the nearest hundredth )
Answer:
The answer to your question is:
Step-by-step explanation:
1.-
2sec
2.-
sec²x - tanxsecx
Answer:
92
Step-by-step explanation:
Answer:
exterior angle = 36°
Step-by-step explanation:
In any polygon
exterior angle + interior angle = 180°
let x be the exterior angle then interior angle is 4x , then
x + 4x = 180
5x = 180 ( divide both sides by 5 )
x = 36
thus exterior angle = 36°
