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3 years ago

10

Academy X + v

1 answer:

bearhunter [10]3 years ago

4 0

A+B=C your lusjis Janis

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Which equations are true?<br>A: -x = -x + x + 0<br>B: -x = 0 + (-x)<br>C: None Of The Above

Leto [7]

Answer: B
Explanation: if you look at A and try to combine like terms, you will add the -x on the right side the the one on the left, cancelling out the x on the left. then you have 0=x+0, and unless x=0, it is not true.
With B, when you add x to the -x, you cancel it out, giving you 0=0, which is true. hope it helps!

3 0

2 years ago

If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2

ipn [44]

Answer:

$g(x)=x+1$

The problem:

Find $g(x)$ if $h(x)=(f \circ g)(x)$ ,

$h(x)=\sqrt[3]{x+3}$ , and

$f(x)=\sqrt[3]{x+2}$ .

Step-by-step explanation:

$h(x)=(f \circ g)(x)$

$h(x)=f(g(x))$

Replace $x$ in $f(x)=\sqrt[3]{x+2}$ with $g(x)$ since we are asked to find $f(g(x))$ :

$\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}$

$\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}$

This implies that $x+1=g(x)$

Let's check:

$(f \circ g)(x)$

$f(g(x))$

$f(x+1)$

$\sqrt[3]{(x+1)+2}$

$\sqrt[3]{x+1+2}$

$\sqrt[3]{x+3}$ which is the required result for $h(x)$ .

6 0

3 years ago

Help with this I don't know how to solve please please please!!

likoan [24]

Answer:

212.5

Step-by-step explanation:

Here's a theorem about triangle areas.

If two similar triangles have sides in the ratio x:y,

then their areas are in the ratio x2:y2

The triangles have sides in the ratio:

LP/LN = 10/25

The two triangles have areas in the ratio 100:625 (4/25)

For every 4 in the small triangle, there are 25 in the larger triangle.

34/4 = 8.5

25 times 8.5 =212.5

6 0

3 years ago

Simplify 4x + 7 + 11x

ozzi

15x plus 7
This is because you just simplify the like terms

5 0

4 years ago

The number of students in an school building that have the flu after t days is given by the function

gulaghasi [49]

Step-by-step explanation:

$p(0) = \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} } = \frac{800}{1 + 49} = \frac{800}{50} = 16$

$200 = \frac{800}{1 + 49 {e}^{ - 0.2t} } \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t} = 800 \\ 9800 {e}^{ - 0.2t} = 600 \\ {e}^{ - 0.2t} = \frac{3}{49} \\ ln( {e}^{ - 0.2t} ) = ln( \frac{3}{49} ) \\ - 0.2t = - 2.793 \\ t = 13.96 = 14$

6 0

3 years ago