Answer:
7 and 13
Step-by-step explanation:
let the 2 numbers be x and y , x > y , then
x = y + 6 → (1)
(x + y) = y - 2 ( multiply both sides by 4 to clear the fraction )
x + y = 4y - 8 ( subtract 4y from both sides )
x - 3y = - 8 → (2)
Substitute x = y + 6 into (2)
y + 6 - 3y = - 8
- 2y + 6 = - 8 ( subtract 6 from both sides )
- 2y = - 14 ( divide both sides by - 2 )
y = 7
Substitute y = 7 into (1)
x = 7 + 6 = 13
The 2 numbers are 7 and 13
The two solutions for the system of equations:
y = x^2+ 5x - 3
y - x = 2
Are:
(-5, -7) and (1, -1)
<h3>How to solve the system of equations?</h3>Here we have the following system of equations:
y = x^2+ 5x - 3
y - x = 2
We can replace the first equation into the second one to get:
(x^2+ 5x - 3) - x = 2
x^2 + 4x - 3 = 2
x^2 + 4x - 3 - 2 = 0
x^2 + 4x - 5 = 0
Using the quadratic formula, we will get the solutions:
The two solutions are:
x = (-4 - 6)/2 = -5
x = (-4 + 6)/2 = 1
To find the values of y, we can evaluate the linear equation:
when x = -5
y - (-5) = -2
y + 5 = -2
y = -2 - 5 = -7
So one solution is (-5, -7)
when x = 1
y - 1 = -2
y = -2 + 1 = -1
The other solution is (1, -1)
Learn more about systems of equations:
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