In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35
Part (a): When 15 people are tested
(i) Number of people expected to pass
This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
Number of people expected to pass = 9 people.
(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%
Part (b): Teenager determined to pass the test no matter how many times
(i) Probability that he passes the test the third time
This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%
(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
E = 1/p
Substituting;
E = 1/0.65 = 1.54 ≈ 2
Therefore, at least two trials will be required.
Answer:
(-3,2)
Step-by-step explanation:
Go where the two coordinates match, you'll see that it's (-3,2).
I see that that's Edge2021, I know how that feels. :/
Hope this helped! :)
Answer:
X=3
Y=2
Step-by-step explanation:
(3+2)2=10
If you use this, please give me brainliest
Answer: provided in the explanation segment
Step-by-step explanation:
here i will give a step by step analysis of the question;
A: Optimization Formulation
given Xij = X no. of units of product i manufactured in Plant j, where i = 1,2,3 and J = 1,2,3,4,5
Objective function: Minimize manufacturing cost (Z)
Z = 31 X11 + 29 X12 + 32X13 + 28X14 + 29 X15 + 45 X21 + 41 X22 + 46X23 + 42X24 + 43 X25 + 38 X31 + 35 X32 + 40X33
s.t
X11 + X12 + X13 + X14 + X15 = 600
X21 + X22 + X23 + X24 + X25 = 1000
X31 + X32 + X33 = 800
X11 + X21 + X31 <= 400
X12 + X22 + X32 <= 600
X13 + X23 + X33 <= 400
X14 + X24 <= 600
X15 + X25 <= 1000
Xij >= 0 for all i,j
B:
Yes, we can formulate this problem as a transportation problem because in transportation problem we need to match the supply of source to demand of destination. Here we can assume that the supply of source is nothing but the manufacturing capability of plant and demand of destination is similar to the demand of products.
cheers i hope this helps!!