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Ksju [112]
3 years ago
13

Complete el cuadro de Punnett que muestra un cruce entre un hombre que es heterocigoto para el tipo de sangre B y una mujer que

es heterocigota para el tipo de sangre A.
Biology
1 answer:
mylen [45]3 years ago
7 0

Answer:

F1) 1/4 = 25% de la porgenie será AB, IAIB

     1/4 = 25% de la progenie será heterocigota para el tipo A, IAi

     1/4 = 25% de la progenie será heterocigota para el gruo B, IBi

     1/4 = 25% de la progenie será homocigota recesiva, ii

Explanation:

  • El gen I determina el tipo de sangre de una persona. Es un gen dialelico que muestra alelo dominante I y recesivo I.
  • En personas de tipo A, los alelos son IA dominante, i recesivo.
  • En personas de tipo B, los alelos son IB dominante, i recesivo
  • IA e IB son codomiantes entre si, lo que signofica que hay un tercer fenotypo IAIB, expresando ambos tipos de sangre juntos.  
  • El alelo i es recesivo siempre.

Genotipo A:

  • IAIA, Homocigota dominante
  • IAi, Heterocigota
  • ii homocigota recesivo

Genotipo B:

  • IBIB, Homocigota dominante
  • IBi, Heterocigota
  • ii homocigota recesivo

Genotipo AB:

  • IAIB, Homocigota dominante

Cruza: un hombre que es heterocigoto para el tipo de sangre B con una    

           mujer que es heterocigota para el tipo de sangre A

Parentales) IBi    x    IAi

Gametos)  IB    i      IA    i

Cuadro de Punnett)

                      IB          i

             IA    IAIB       IAi

               i      IBi          ii

F1) 1/4 = 25% de la porgenie será AB, IAIB

     1/4 = 25% de la progenie será heterocigota para el tipo A, IAi

     1/4 = 25% de la progenie será heterocigota para el gruo B, IBi

     1/4 = 25% de la progenie será homocigota recesiva, ii

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