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2 years ago

A line has this equation:y=1/4x-1. what’s a perpendicular line that goes through (3,-8)

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer:

y = -4x + 4

Step-by-step explanation:

y = (1/4)x - 1

m = (1/4)

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/4)

$= (-1)*\frac{4}{1}\\\\=-4$

(3 , -8)

y - y1 =m(x -x1)

y -[-8] = -4(x - 3)

y + 8 = -4x + 12

y = -4x + 12 - 8

y = -4x + 4

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Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

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More can be learned about trigonometric identities at brainly.com/question/24496175

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