All categories

2 years ago

A line has this equation:y=1/4x-1. what’s a perpendicular line that goes through (3,-8)

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer:

y = -4x + 4

Step-by-step explanation:

y = (1/4)x - 1

m = (1/4)

Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/4)

$= (-1)*\frac{4}{1}\\\\=-4$

(3 , -8)

y - y1 =m(x -x1)

y -[-8] = -4(x - 3)

y + 8 = -4x + 12

y = -4x + 12 - 8

y = -4x + 4

You might be interested in

Which is an example of quantitative data?

mixer [17]

Answer:

A. the number of textbooks in a classroom

Step-by-step explanation:

quantitative data is information about quantities; that is, information that can be measured and written down with numbers.

8 0

3 years ago

Read 2 more answers

Uppose a triangle has a,b and c what must be true?

alexdok [17]

Obtuse: b^2 + c^2 > a^2

Right: b^2 + c^2 = a^2

Acute: b^2 + c^2 < a^2

A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2

So, your Answer would be (B)
Hope this helps!!.!

6 0

2 years ago

Read 2 more answers

Find the value of X and a missing angel in this triangle

shepuryov [24]

Answer:

x=175

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

the table shows the fraction of votes that each candidate received. if 230 students voted, how many students voted for each cand

zaharov [31]

3/5=6/10 so Naomi got 138.
Luke got 69.
And Natalie got 23.

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

1 year ago