Answer:
T = 19.75 N
Explanation:
given,
mass of ball = 0.25 Kg
radius = 0.5 m
frequency = 2 s⁻¹
tension in the string = ?
angular velocity
ω = 2 π f
ω = 2 π x 2
ω = 12.57 rad/s
tension on the string is equal to the centripetal force
T = m ω² r
T = 0.25 x 12.57² x 0.5
T = 19.75 N
Tension in the string is equal to T = 19.75 N
Power= current*voltage or P=IV
so 16 watts=I*7 volts
divide on both sides to isolate I so you get
I= 16/7 which is about 2.3 amps
Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;
where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
When you ask for help with a crossword clue, don't forget to tell us how many letters it has. For this one, see if "temperature" fits the space.
Answer:
sorry not sure but i can try help with telling you this...
Explanation:
alls you havs to do is ask the internet and it will tell you
