All categories

2 years ago

A geyser shoots water straight up into the air with a velocity of 28.0 m/s. how

Physics

1 answer:

Fed [463]2 years ago

3 0

The maximum height reached by the water before it starts coming back down is 40 m.

<h3>Maximum height reached by the water</h3>

The maximum height reached by the water before it starts coming back down is calculated by applying the principle of conservation of energy.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = (v²)/(2g)

h = (28²)/(2 x 9.8)

h = 40 m

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

You might be interested in

Which of the following is not a constant or control for this experiment?

SCORPION-xisa [38]

D.the amount of time in sun

8 0

3 years ago

Read 2 more answers

Electromagnetic waves are commonly referred to as _________

mart [117]

It’s going to be both answer A and B but if you can only answer one then it’s going to be B

3 0

2 years ago

Can someone help me ASAP

Phantasy [73]

Well I don't know. Let's actually LOOK at the picture and see if that helps.

A, B, C, and D all have the same TOTAL length, but A has the most waves crammed into that same total length.

By golly, that means the length of <u><em>each</em></u> wave in A must be shorter than each wave in B, C, or D.

The correct choice is <em> A </em>. Looking at the picture did the trick !

7 0

2 years ago

A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca

viva [34]

Answer:

$a=0.2*10^{-5}g$

Explanation:

From the question we are told that:

Mass $M=180=>0.18kg$

Charge $Q=18mC=18*10^-^3C$

Velocity $v=2.2m/s$

Length of Wire $L=8.6cm=>0.086$

Current $I=30A$

Generally the equation for Magnetic Field of Wire B is mathematically given by

$B=\frac{\mu_0*I}{2\pi*l}$

$B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}$

$B=6.978*10^{-5}T$

Generally the equation for Force on the plane F is mathematically given by

$F=qvB$

Therefore

$ma=qvB$

$a=\frac{qvB}{m}$

$a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}$

$a=2.37*10^{-5}$

Therefore in Terms of g's

$a=\frac{2.37*10^{-5}}{9.8}$

$a=0.2*10^{-5}g$

8 0

2 years ago

Gas hydrates are used _____.

Nonamiya [84]

Hope this helps mark brainest plz

4 0

3 years ago

Read 2 more answers