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Ilia_Sergeevich [38]

3 years ago

13

The length of a rectangle is 12ft longer than twice the width. If the perimeter is 108ft, find the length and width of the recta

ngle.

1 answer:

Tcecarenko [31]3 years ago

3 0

Answer:

Down below

Step-by-step explanation:

P = 2L + 2W

P = 108

L = 2W+12

108 = 2(2W+12) + 2W

108 = 4W + 24 + 2W

108 = 6W + 24

84 = 6W

14 = W

W = 14

If the width is 14, then the length is twice that plus 12, or 38

38 + 38 + 14 + 14 = 108

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Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

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$\rm\implies y = 3^2+3-6\\$

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