Question

The length of a rectangle is 12ft longer than twice the width. If the perimeter is 108ft, find the length and width of the rectangle.

Answer 1

Answer:

Down below

Step-by-step explanation:

P = 2L + 2W

P = 108

L = 2W+12

108 = 2(2W+12) + 2W

108 = 4W + 24 + 2W

108 = 6W + 24

84 = 6W

14 = W

W = 14

If the width is 14, then the length is twice that plus 12, or 38

38 + 38 + 14 + 14 = 108