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MAXImum [283]
3 years ago
11

Help please (will give brainliest)

Mathematics
1 answer:
ycow [4]3 years ago
5 0
Sin <P = opp/hyp = 12/13
m <P = 67.38 degrees
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What is the area of a regular pentagon with a side length of 9 millimeters and an apothem length of 6.2 millimeters?
Kazeer [188]
A Pentagon can be broken up into 5 equal triangles. Area of the Pentagon is the sum of all the 5 triangles.

Area of the pentagon = 5 ( 1/2 x 6.2 x 9) = 139.5 mm²

Answer: 129.5 mm² (Answer D)
5 0
3 years ago
Solve for the surface area.
Feliz [49]

Answer:

382.5

Step-by-step explanation:

9x10=90

9x9=81

13.5x9=121.5

9x10=90

180+81+121.5= 382.5

3 0
3 years ago
Read 2 more answers
a phone company offers two monthly charge, in Plan a, the customer pays a monthly fee of $40.10 and then an additional 4 cents p
Charra [1.4K]

Answer:

x > 1.7 minutes

The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

Step-by-step explanation:

The two plans must be defined by the equation of the line y = mx + b, where

y = plan

m = slope or payment of additional cents per minute

x = time expressed in minutes

For Plan A, we have

y = 4x + 40.10 (Equation A)

While plan B is defined as

y = 7x + 35 (Equation B)

Plan A must be less than Plan B,

4x + 40.10 < 7x + 35

We put the “x” on the left side and the independent terms on the right side,

4x - 7x < 35 - 40.10

We add algebraically,

-3x < -5.10

We multiply the equation by -1 to eliminate the two “minus” signs, changing the inequality sign,

3x > 5.10

We isolate x,

x > 5.10 / 3

We solve, calculating the value of x,

x > 1.7 minutes

The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

7 0
3 years ago
Jamal's deck is in the shape of a polygon and is shown on the grid below.(-8,6)(6,6)o[(-8, -4),(6,-4)What is the area of Jamal's
PSYCHO15rus [73]

Let;

A(-8,6) B(6,6) C(6, -4) D(-8, -4)

Let's find the length AB

x₁= -8 y₁=6 x₂=6 y₂=6

We will use the distance formula;

d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

=\sqrt[]{(6+8)^2+(6-6)^2}=\sqrt[]{14^2+0}=14

Next, we will find the width BC

B(6,6) C(6, -4)

x₁= 6 y₁=6 x₂=6 y₂=-4

substitute into the distance formula;

d=\sqrt[]{(6-6)^2+(-4-6)^2}

=\sqrt[]{(-10)^2}=\sqrt[]{100}=10

Area = l x w

= 14 x 10

= 140 square units

7 0
1 year ago
What was the day of the week on Alex’s 39 day of his trip
vitfil [10]

Answer:

what year was his trip? I can figure it out I just need the year

Step-by-step explanation:

6 0
4 years ago
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