Question

What is the radius of a hemisphere with a volume of 45729 in, to the nearest tenth of an inch?

Answer 1

Answer:

Step-by-step explanation:

Use the volume of a sphere formula and then multiply it by .5 to get half of it, since a hemisphere is half of a sphere. Doing that gives us the formula:

$V=\frac{4}{3}\pi r^3\frac{1}{2}$ which simplifies to

$V=\frac{2}{3}\pi r^3$ . Now, filling in what we were given:

$45729=\frac{2}{3}\pi r^3$ which simplifies a bit to

$137187=2\pi r^3$. We divide by 2π to get

$2183.98918=r^3$ and take the cubed root on your calculator to get that

r = 27.9"

Answer 2

✏Answer:

$Volume= 45729in^3$

$Radius=r$

$2/3\pi r^3=45729$

$r^3=3*45729\\~~~~------\\~~~~~~2*3.14$

$r^3=21845.06$

$r=27.95~in$

✂-------------

hope it helps...

have a great day!!