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Soloha48 [4]
2 years ago
6

Solve PLEASE HELP AND HURRY!

Mathematics
1 answer:
Luda [366]2 years ago
3 0

Answer:

it's -7 1/3 because since the equation is all negative you would just simply add the -5 and -2 1/3

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if a clocks second hand is 7 in. long , how many feet does it travel in 24 hr? how many miles does it travel?
frozen [14]

Answer: Question 1 -  15 ft is how it travels. Question 2 -  95 miles is what it travels.

Step-by-step explanation: Question 1 -  15 ft is how it travels, it goes really slow and then fast.

Question 2 -  95 miles is what it travels because you got the short hand, the hour hand, the long hand, the minute hand. It goes really slow and then really fast.

7 0
3 years ago
15−7×2+23 help...................................
Helen [10]

Answer:

24

Step-by-step explanation:

PEMDAS: 15-14+23

1+23

24

8 0
2 years ago
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Mr.Johnson leaves on a trip planning to travel 24 mph
Artist 52 [7]
Ummm is this a full question?
4 0
3 years ago
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One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
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What is the y-intercept of this line?<br> y = x - 2<br> b = [?]
Nostrana [21]

Answer:

-2

Since b = -2, the y intercept is -2.

4 0
2 years ago
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