D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
I know it's not the answer ur looking for but [mathaway] will help u ace ur test
Answer:
Add the exponents
Step-by-step explanation:
Product Rule: am ∙ an = am + n, this says that to multiply two exponents with the same base, you keep the base and add the powers.
EX:
x multiplied by x^5=x^6
So what your saying is that James can type 5 words and Anne can type 8 words right? And James types 150 so how many can Anne type? Is that what your asking?