All categories

3 years ago

HELP HELP HELP ILL MARK BRAINLIEST

Mathematics

2 answers:

Rufina [12.5K]3 years ago

7 0

Answer 1 is correct! it is an SRS

Leya [2.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

PLEASE HELP ME THESE ARE MY LAST POINTS PLEASEEE

Julli [10]

About 16 copies cost the same amounts

5 0

3 years ago

Read 2 more answers

C++ the length of a rectangle is stored in a double variable named length, the width in one named width. write an expression who

Blizzard [7]

Sqrt(pow(width,2) + pow(length ,2)

7 0

3 years ago

What is DC if AC = 10 cm, BC = 6 cm, and EC = 12 cm? using the options below

NNADVOKAT [17]

The answer is A. Or 5 cm.

Hope this helps,

kwrob

8 0

4 years ago

Read 2 more answers

FRAME AN EQUATION AND SOLVE IT. NEED HELP ASAP I only have 5 minutes!

lawyer [7]

Answer:

The answer to your question is 125

Step-by-step explanation:

x = 25 X 5= 125.

The required number is 125.

I hope this helps and have a good day!

3 0

2 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago