(2n + 5k)^2 = (2n + 5k)(2n + 5k)
Here we need to use FOIL
First - 2n * 2n = 4n^2
Outside - 2n * 5k = 10nk
Inside - 5k * 2n = 10nk
Last - 5k * 5k = 25k^2

That gives us 4n^2 + 10nk + 10nk + 25k^2, we can combine 10nk + 10nk to give 20nk, and a final equaion of 4n^2 + 20nk + 25k^2

4 0

4 years ago

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Please help me with the problem

mixas84 [53]

Let's see what we're working on here

$\frac{1}{2} - 2(m) =?$
? = 0
$Simplify this →$ $\frac{1}{2}$

$\frac{1}2y} - 2(m) = ?$

$\frac{2(m)(2)}{2}$

$\frac{1 - 4(m)}{2} = ?$

$\frac{1 - 4(m)}{2} = 2$

$-4(m) + 1 = 0$
Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1
Multiply( ×) the number -1 to your sides for this part of the equation

Therefore, the value of m is $\frac{1}{4}$
$m = \frac{1}{4}$

3 0

4 years ago

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What whole number come right before 110?

slava [35]

Answer:

109?

Step-by-step explanation:

6 0

3 years ago

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Need a bit of assistance with this problem here.