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Artyom0805 [142]
3 years ago
15

I need help on finding the measure of each angle on a rectangle

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

1  65

2 65

3 25

4 25

5 50

6 130

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A guy wire to a tower makes a 71° angle with level ground. At a point 36 ft farther from the tower than the wire but on the same
lilavasa [31]

The length of the wire is 37.15 ft

<u>Explanation:</u>

The figure is attached for the reference.

tan (71) = \frac{y}{x}

tan (36) = \frac{y}{36+x}

So,

tan(36) (36 + x) = y

tan(71) = \frac{tan (36) (36 + x )}{x}

2.9 = \frac{0.73 (36 + x)}{x} \\\\2.9 x = 26.28 + 0.73x\\\\2.17x = 26.28\\\\x = 12.11 ft

Substituting x = 12.11 ft in equation 1:

tan (71) = \frac{y}{12.11} \\\\2.9 X 12.11 = y\\\\y = 35.119 ft

Length of the wire, z = \sqrt{x^2 + y^2}

So,

z = \sqrt{(12.11)^2 + (35.119)^2} \\\\z = \sqrt{146.6521 + 1233.3442} \\\\z = 37.15 ft

Therefore, the length of the wire is 37.15 ft

7 0
3 years ago
13.
Andreyy89

Answer: 24 yards

Step-by-step explanation:

4 0
3 years ago
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Find x if:<br> 1. 125x^3=b^9<br><br> 2.16x2=1
vitfil [10]
1   x^3 = b^9 / 125

x =  b^3 / 5 

2.   x^2 = 1 /2.16

x = sqrt 1/2.16

x =  +/- 0.68 to nearest hundredth

4 0
3 years ago
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ra1l [238]

Answer:

  • <em>The actual temperature after the freezer was on for five minutes could be </em><u><em>18ºF or 12ºF</em></u>

Explanation:

First, you must find the y-value returned by the line in the graph for a time (x) of five minutes, and then use the deviation of 3º to conclude the range of the real temperature.

<u>1. y- value at x = 5 min.</u>

The trend line (blue line in the graph) passes through the point (5,15), which means that it predicts a temperature of 15ºF when the time (x) is 5 minutes, or five minutes after the freezer was turned on.

<u>2. Actual temperature value</u>

It is stated that the temperature was actually three degrees from what the trend line shows, that means that the actual temperature could be 3ºF more or 3ºF less than the predicted temperature of 15ºF.

Mathematically:

  • Temperature = 15ºF ± 3ºF

  • Temparature = 15ºF + 3ºF or 15ºF - 3ºF

  • Temperature = 18ºF or 12ºF ← answer.
8 0
4 years ago
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