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3 years ago

Determine if the following system of equations has no solutions, infinitely many

Mathematics

1 answer:

sleet_krkn [62]3 years ago

6 0

Answer:

Exactly one solution

Step-by-step explanation:

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What is the 5th term of an arithmetic sequence of 20 terms with first and last terms of 2 and 59, respectively

Verizon [17]

Answer:

Step-by-step explanation:

aₙ = a₁ + (n-1)*d

59 = 2 + (20-1) * d

59 = 2 + 19d

19d = 59-2 = 57

d = 3

5th term: a₅ = 2 + 4 * 3 = 14

8 0

3 years ago

Simplify. (-2)^-3 A.-8 B.-1/8 C.1/8 D.8

DiKsa [7]

ANSWER

${( - 2)}^{ - 3} =- \frac{1}{ 8}$

EXPLANATION

We want to simplify;

${( - 2)}^{ - 3}$

Recall that,

${a}^{ - m} = \frac{1}{ {a}^{m} }$

${( - 2)}^{ - 3} = \frac{1}{{( - 2)}^{ 3}}$

We multiply out to get,

${( - 2)}^{ - 3} = \frac{1}{{- 2} \times - 2 \times - 2}$

${( - 2)}^{ - 3} = \frac{1}{ - 8}$

The correct choice is B.

6 0

3 years ago

Which expression is equivalent to? I need the answer quick please

myrzilka [38]

Answer:

Step-by-step explanation:

The answer is C im not sure

5 0

3 years ago

Read 2 more answers

Please help me !!!! Will mark brainliest

stich3 [128]

Answer:

The value of x is 108°

Step-by-step explanation:

Given interior angles of parallelogram are:

$\frac{2}{3}x, x, \frac{2}{3}x\ and x$

The sum of interior angles of a parallelogram is 360°.

We will use this information to find the value of x.

So adding up all the angles and putting the sum equal to 360 we get,

$x+\frac{2}{3}x+x+\frac{2}{3}x = 360$

$2x+\frac{2}{3}x+\frac{2}{3}x = 360\\2x + \frac{4}{3}x = 360$

Taking LCM on left side of the equation, as it involves fraction

$\frac{6x+4x}{3} = 360\\\frac{10x}{3} = 360$

Multiplying both sides by 3

$\frac{10x}{3} * 3 = 360 * 3\\10x = 1080$

Dividing both sides by 10

$\frac{10x}{10} = \frac{1080}{10}\\x = 108$

Hence,

The value of x is 108°

3 0

3 years ago

Which of the following is the solution to 4|x+2|>16

marusya05 [52]

Answer:

x < - 6 or x > 6

Step-by-step explanation:

Inequalities of the type | x | > a, always have solutions in the form

x < - a or x > a

given 4| x + 2 | > 16 ( divide both sides by 4 )

| x + 2 | > 4 ← in the above form, hence

x + 2 < - 4 or x + 2 > 4 ( subtract 2 from both sides of both inequalities )

x < - 6 or x > 6 ← solution

4 0

4 years ago