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Licemer1 [7]
2 years ago
13

In ACDE, mC = (5x + 18)°, m_D = (3x + 2)°, and mZE = (x + 16). Find mZD.

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0
If you expect to ask your question and only for 5 points nobody’s going to answer your question anytime soon.
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Solve the equations: |x-1|/|x-1| = 1
Tanya [424]
X = 2
The absolute value lines basically just serve as parentheses in this equation.
(2-1)/(2-1) = 1
(1)/(1) = 1
6 0
3 years ago
Read 2 more answers
Help Please I need help with everything shown on this page
evablogger [386]
This question is all about dimensional analysis.  The whole idea behind dimensional analysis is that you multiply a starting value with different conversion factors to cancel out units you don't want to tern the value into the units that you do want.  The conversion for yards to feet can be written as 3 feet/yard (this is the conversion factor it can be written as 3feet/1yard or 1yard/3feet, it depends on what you are starting with).  If you start out with yards and and want to go to feet you have to multiply the number of yards by 3feet/yard so that the yards cancel out leaving you with feet.  If start out with feet and want to go to yards you divide the number of feet by 3feet/yard so that the feet cancel out and you are left with yards.

In your question Tom is trying to go from feet to yards.  Therefore he has to divide the number of feet by 3feet/yard to get feet to cancel out.  His mistake was that he multiplied by 3feet/yard instead of divide by 3feet/yard.  The correct way do it is divide 379 feet by 3feet/yard to get 126.33 yards.

Let me know if anything is unclear to you in the comments.  This is a very important skill to learn since this is the basis of many high school and college science classes.
I hope this helps.
7 0
3 years ago
What is the value of b<br> 2b + 8 − 5b + 3 = −13 + 8b − 5
Yuri [45]

Answer:

See below.

Step-by-step explanation:

2b + 8 − 5b + 3 = −13 + 8b − 5

Reorder like terms.

2b-5b+8+3=8b-13-5

Combine those like terms. Then solve.

-3b+11=8b-18

      -11       -11

-3b=8b-29

-8b -8b

-11b=-29

/-11    /-11

b=2.64

-hope it helps

3 0
2 years ago
Read 2 more answers
2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A
Leokris [45]

Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let \mu = <u><em>population mean length of the board</em></u>.

So, Null Hypothesis, H_0 : \mu = 2564.0 millimeters    {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, H_A : \mu \neq 2564.0 millimeters      {means that the boards are either too long or too short}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                             T.S.  =  \frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }  ~  t_n_-_1

where, \bar X = sample mean length of boards = 2559.5 millimeters

            s = sample standard deviation = 15.0 millimeters

             n = sample of boards = 26

So, <em><u>the test statistics</u></em> =  \frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }  ~   t_2_5

                                     =  -1.529    

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

4 0
4 years ago
Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north.
mylen [45]
G=t negative 320+f5 t=b

6 0
3 years ago
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