This question is all about dimensional analysis. The whole idea behind dimensional analysis is that you multiply a starting value with different conversion factors to cancel out units you don't want to tern the value into the units that you do want. The conversion for yards to feet can be written as 3 feet/yard (this is the conversion factor it can be written as 3feet/1yard or 1yard/3feet, it depends on what you are starting with). If you start out with yards and and want to go to feet you have to multiply the number of yards by 3feet/yard so that the yards cancel out leaving you with feet. If start out with feet and want to go to yards you divide the number of feet by 3feet/yard so that the feet cancel out and you are left with yards.

In your question Tom is trying to go from feet to yards. Therefore he has to divide the number of feet by 3feet/yard to get feet to cancel out. His mistake was that he multiplied by 3feet/yard instead of divide by 3feet/yard. The correct way do it is divide 379 feet by 3feet/yard to get 126.33 yards.

Let me know if anything is unclear to you in the comments. This is a very important skill to learn since this is the basis of many high school and college science classes.
I hope this helps.

7 0

3 years ago

What is the value of b 2b + 8 − 5b + 3 = −13 + 8b − 5

Yuri [45]

Answer:

See below.

Step-by-step explanation:

2b + 8 − 5b + 3 = −13 + 8b − 5

Reorder like terms.

2b-5b+8+3=8b-13-5

Combine those like terms. Then solve.

-3b+11=8b-18

-11 -11

-3b=8b-29

-8b -8b

-11b=-29

/-11 /-11

b=2.64

-hope it helps

3 0

2 years ago

Read 2 more answers

2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A

Leokris [45]

Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let $\mu$ = population mean length of the board.

So, Null Hypothesis, $H_0$ : $\mu$ = 2564.0 millimeters {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 2564.0 millimeters {means that the boards are either too long or too short}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean length of boards = 2559.5 millimeters

s = sample standard deviation = 15.0 millimeters

n = sample of boards = 26

So, the test statistics = $\frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }$ ~ $t_2_5$

= -1.529

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

4 0

4 years ago

Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north.

mylen [45]

G=t negative 320+f5 t=b

6 0

3 years ago