My name is Chris I'm sorry for being so late but no I got it and I will be there for being such a great time with you and your team and I will get back to you are you still looking I'm sorry for being a little bump it to the only thing I can think of is that a little bit of time
Answer:
Explanation:
There are many weaknesses/vulnerabilities, some of which are the following...
Default Network Hardware, many individuals will go out and buy a new router and install it in their home. These devices come with a preset configuration including a preset security password which is many times a default password used for every router of the same model. This can be easily obtained by anyone who can then access the network.
Access Point hacking, an experienced individual can use a packet sniffer to detect the SSID that is frequently sent from the router in order to create an access point to be able to access the network.
WEP encryption is another vulnerability. These are very low security passwords that can be cracked using different software in a short period of time.
These are some of many vulnerabilities that wireless local networks have, but there are also many precautions and security measures that can be taken to prevent them.
Answer:
// here is code in c++ to find the approx value of "e".
#include <bits/stdc++.h>
using namespace std;
// function to find factorial of a number
double fact(int n){
double f =1.0;
// if n=0 then return 1
if(n==0)
return 1;
for(int a=1;a<=n;++a)
f = f *a;
// return the factorial of number
return f;
}
// driver function
int main()
{
// variable
int n;
double sum=0;
cout<<"enter n:";
// read the value of n
cin>>n;
// Calculate the sum of the series
for (int x = 0; x <= n; x++)
{
sum += 1.0/fact(x);
}
// print the approx value of "e"
cout<<"Approx Value of e is: "<<sum<<endl;
return 0;
}
Explanation:
Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".
Output:
enter n:12
Approx Value of e is: 2.71828
Answer:
if (option1.equals(option2)){
rsvp = true;
}
System.out.println(rsvp);
A full program is given in the explanation section
Explanation:
import java.util.Scanner;
public class Option {
public static void main(String[] args) {
boolean rsvp = false;
int selection;
String option1,option2;
Scanner in = new Scanner(System.in);
option1 = in.next();
option2 = in.next();
if (option1.equals(option2)){
rsvp = true;
}
System.out.println(rsvp);
}
}
Answer:
Following are the response to the given question:
Explanation:
Build a spring, sink, vertices, and vertices for each car for a household. Every unit in the stream is a human. Attach the source from each vertical of a family with such a capacity line equivalent to the family size; this sets the number of members in each household. Attach every car vertices to the sink with the edge of the car's passenger belt; this assures the correct number of people for every vehicle. Connecting every vertex in your household to any vertex in your vehicle with a capacity 1 border guarantees that one family member joins a single car. The link between both the acceptable allocation of people to vehicles as well as the maximum flow inside the graph seems clear to notice.
