We can solve by figuring the area of the rectangle then add it to the area of the semicircle.
Area of the rectangle: length · width = 6 · 10 = 60 ft²
Area of the semicircle: (πd²)/8 = (3.14 · 6²)/8 = (3.14 · 36)/8 = 14.13 ft²
Total area of the figure: 60 + 14.13 = 74.13 ft² ≈ 74 ft²
Follow pemdas
2+(1/2) +34- (1/10)
2.5 + 34 - .1
36.5-.1
36.4
1. -3x -20
2. -6x-16
3. -14-x
The answer of number 4 is 57+36 x 0.001
The range of <span><span><span><span><span><span><span>ta</span>n</span>g</span>e</span>n</span>t</span><span><span><span><span><span><span>ta</span>n</span>g</span>e</span>n</span>t</span></span>
is all real numbers.
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