Question

Exactly 10 disks are in a bowl. Each is marked with a different counting number selected from 1-10. Gina and Monique each select 5 disks. Two of Gina's disks are 2 and 8. Two of Monique's disks are 7 and 9. What is the largest sum that Gina's disks can have?

Answer 1

Answer: 31

Step-by-step explanation:

The two disks that we know Gina has are: 2 and 8.

We want to find tha largest sum that Gina's disks can have:

This means that the other 3 disks must be the largest possible ones.

We know that Monique has the disks 7 and 9.

The already taken values are: 2, 7, 8, and 9.

The largest values remaining are:

10, 6 and 5.

Then the largest sum that Gyna's disks can have is given by the scenario where Gina draws these 3 disks, and the sum will be:

2 + 8 + 10 + 6 + 5 = 31