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3 years ago

Please answer my question, and if you can please provide an explanation so I can learn from it. 50 POINTS.

Mathematics

2 answers:

gayaneshka [121]3 years ago

8 0

Answer: -4x - y = -50 (second option)

Step-by-step explanation: The only way lines won't intersect is if they're parallel. Parallel lines have the same slope --> the line must have a slope of -4x.

Option 1:

y = 4x - 200 (add 4x to both sides)
Different slope.

Option 2:

-y = 4x - 50 (add 4x to both sides)
y = -4x + 50 (divide by -1)
Same slope.

Option 3:

-y = -4x - 200 (subtract 4x from both sides)
y = 4x + 200 (divide by -1)
Different slope.

Option 4:

-y = -4x - 50 (subtract 4x from both sides)
y = 4x + 50 (divide by -1)
Different slope.

il63 [147K]3 years ago

7 0

Answer:

-4x - y = -50 or b on my flvs

Step-by-step explanation:

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sveta [45]

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2 years ago

What is the size of the sample space for flipping 7 coins? Write your answer as a single integer.

Elenna [48]

I think the answer is 6

4 0

2 years ago

Read 2 more answers

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

What is the length of DE?

miskamm [114]

Answer:

Step-by-step explanation:

If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.

AC *CB = CD CE

4 * (10-4) = CD * 8

4 * 6 = 8 *CD

24 = 8 CD

Divide each side by 8

24/8 = CD

3 = CD

We want the length DE

DE = CD + CE

= 3 + 8

DE = 11

5 0

3 years ago

A tree and a building stand side by side. The 5-foot tall tree cast a shadow of 12 feet. If the building is 80 feet tall, how lo

SpyIntel [72]

Answer:

The shadow of the building = 192 ft.

Step-by-step explanation:

∵ There is a proportional relation between the heights of the tree and the building and their shadows

∴ Height tree/height building = shadow tree/shadow building

$\frac{5}{80}=\frac{12}{x}$

x = $\frac{(80)(12)}{5}$ = 192 ft ⇒ x is the length of the shadow of the building

3 0

2 years ago