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Arlecino [84]
3 years ago
13

Choose yes or no weather the expression are equivalent 2(8f-5) and 10f-10

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0

Step-by-step explanation:

I think the answer is no

andreyandreev [35.5K]3 years ago
8 0

Answer:

no

Step-by-step explanation:

once distributed, 2(8f-5) becomes 16f-10 which is not equivalent to 10f-10

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What is the sum of the geometric series in which a1 = −5, r = 3, and an = −405?
marysya [2.9K]
An = a1 * r^(n-1)

-405 = -5*3^(n-1)

3^(n-1) = 81

3^4 = 81  so n-1 = 3  and n =  4

Sn  = S4  =  -5 (1 - 3^4)   / ( 1 - 3)   =  400 / -2 = -200 Answer
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Which set of ordered pairs does not represent a function?
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Answer:

The second choices is the answer

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Read 2 more answers
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
How do you write two hundred fifty-two and thirty-one ten thousandths
ryzh [129]

Answer:

252.3110

Step-by-step explanation:

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3 years ago
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