Since supplementary angles are angles that equal to 180, you first need to subtract 40 from 180 to find out what the equation equals. This is the layout of the equation. 140=4x+20. Next you subtract 20 from each side, 120=4x then you divide by 4 four, x=30.
First subtract 100v² from both sides to get:
C²L²=100c²-100v²
Then divide both sides by C²:
L²=(100c²-100v²)/C²
Then take the square root of both sides:
L=+ or - the square root of (100c²-100v²)/C²
Answer:
There would be 15 girls and 21 boys
I draw the two triangles, see the picture attached.
As you can see, angle 1 and 2 are vertically opposite angles because they are formed by the same two crossing lines and they face each other.
Angles <span>ABQ and QPR, as well as angles BAQ and QRP, are alternate interior angles because they are formed by </span><span>two parallel lines crossed by a transversal, and they are inside the two lines on opposite sides of the transversal.</span>
Hence, Allison's correct claims are:
1 = 2 because they are vertically opposite angles. BAQ = QRP because they are alternate interior angles. Therefore Allison, in order to prove her claim, can use the AA similarity theorem: if two angles of a triangle are congruent to two angles of the other triangle, then the two triangles are similar.
it is a polygon and it would be a decagon since there are 10 sides