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3 years ago

What is the answer NEED HELP ASAP

Mathematics

1 answer:

Feliz [49]3 years ago

4 0

Answer:

244,140,625

Step-by-step explanation:

5×5×5×5 = 625

5×5×5×5×5×5×5×5 = 390,625

390,625×625= 244,140,625

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How do I do this? (3x^2+8)-(2x^2+1) So first I add like terms? 5x^2 + 8 + 1

Gemiola [76]

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= 3x² + 8 - 2x² - 1
= 3x² - 2x² + 8 - 1
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Percentage increase for 5 cups and 8 cups

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3 years ago

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Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

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2 years ago

Let $z$ be a complex number such that $z^5 = 1$ and $z \neq 1.$ Compute

snow_lady [41]

Answer:

The answer is 4

Step-by-step explanation: i did it

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2 years ago

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evablogger [386]

Answer:

1, 3, 4

Step-by-step explanation:

Among these answer choices, you're looking for two expressions separated by a minus sign. Choice 2 is only one expression, so does not meet the required criterion.

1. 6(x+7)-2

3. 4f-2g

4. 3xyz-10

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3 years ago