Answer:
Area of floor = 21.6m2
area of tile = 576cm2=0.0576m2
now,
number of tiles = 21.6/0.0576
= 375
0° 42' 48.6".
Conversion: d = int(.7135°) = 0°m = int((.7135° - 0°) × 60) = 42's = (.7135° - 0° - 42'/60) × 3600 = 48.6".7135°= 0° 42' 48.6"
How to convert decimal degrees to degrees,minutes,secondsOne degree (°) is equal to 60 minutes (') and equal to 3600 seconds ("):
1° = 60' = 3600"
The integer degrees (d) are equal to the integer part of the decimal degrees (dd):
d = integer(dd)
The minutes (m) are equal to the integer part of the decimal degrees (dd) minus integer degrees (d) times 60:
m = integer((dd - d) × 60)
The seconds (s) are equal to the decimal degrees (dd) minus integer degrees (d) minus minutes (m) divided by 60 times 3600:
s = (dd - d - m/60) × 3600
Answer: [B]: "not enough information [provided]" .
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{since we are not given a diagram; and, for that matter, we are not given ANY informatioabout the where "Point A" is located—AT ALL; or for that matter, ANY MENTION WHATSOVER about "Point A"—within THIS VERY QUESTION —
{not to mention, for instance, the fact that there is no information as regard to any angle containing "Point A" in relation to the [particular angle in THIS VERY QUESTION — (which does NOT mention any angle containing "Point A" {as aforementioned/as can be inferred}.
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Note: By the way, thank you for providing "answer choices". Otherwise, this question would be an "improper question" for "incomplete question content"/ or perhaps: "question is illogical".
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I hope that my explanation —albeit lengthy and superfluous — makes sense. _________________________________________
If you need furhter explanation, Please reply to this answer. Best wishes!
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secA=√2
secA=sec45
A=45°
3cos²45+5tan²45/ 4tan²A-sin²45
= 3(1/√3)²+5(1)² / 4(1)²-(1/√2)²
=3/2+5/4-1/2
=13/7
Answer:
No solutions
Step-by-step explanation:
|-2x-10| + 4 = 2
Subtract 4 from each side
|-2x-10| + 4-4 = 2-4
|-2x-10| = -2
The absolute value is negative so there are no solutions.
Absolute values are always positive, so they cannot be negative.