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Ksivusya [100]
3 years ago
10

If an object is projected upward with an initial velocity of 126 ft per​ sec, its height h after t seconds is h= -16^2+126t. Fin

d the height of the object after 5 seconds
Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

Answer:

230 ft  is the height of the object after 5 seconds

Step-by-step explanation:

As per the statement:

If an object is projected upward with an initial velocity of 126 ft per​ sec.

The height h after t seconds is given by:

h(t) = -16t^2+126t

We have to find the height of the object after 5 seconds.

At t = 5 seconds

h(5) = -16(5)^2+126(5)

⇒h(5) = -16 \cdot 25+630

⇒h(5) = -400+630

Simplify:

h(5) = 230 ft

Therefore, the  height of the object after 5 seconds is, 230 ft

Phoenix [80]3 years ago
3 0
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
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