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2 years ago

Can someone do d) and e) for me please !! due soon

Mathematics

1 answer:

Arlecino [84]2 years ago

5 0

Step-by-step explanation:

sorry I was only able to solve E

I hope it helps

the answer is in the image above

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A company ships a cube with side lengths of 2 feet in a crate that is a larger cube with side lengths of 4 feet. Packing materia

Andreas93 [3]

Answer:

yeah tbh i wanna know to

Step-by-step explanation:

sorry

6 0

3 years ago

2 Points

liraira [26]

Two or zero expresses the possible number of positive real solutions for the given polynomial equation.

Answer: Option D

Step-by-step explanation:

Given equation:

$x^{3}-4 x^{2}-7 x+28=0$

First, we put hit and trial method to find out the one solution. So, if we put x=4 then the above expression will become zero. We can also write the above expression as

$(x-4) \times\left(x^{2}-7\right)=0$

We know the formula, $a^{2}-b^{2}=(a+b)(a-b)$ , make use of this, we get

$(x-4) \times(x-\sqrt{7}) \times(x+\sqrt{7})=0$

So, $x=4, \sqrt{7},-\sqrt{7}$

Hence, from the above expression, we have three values of x as x= 4, 2.64 and -2.64

8 0

3 years ago

Help pleasee don’t know what I’m doing lol

Ksju [112]

Answer:

D. $4\sqrt{3}$ in

Step-by-step explanation:

Hope this helps!

7 0

3 years ago

Read 2 more answers

Find f(a), f(a+h), and 71. f(x) = 7x - 3 f(a+h)-f(a) h if h = 0. 72. f(x) = 5x²

Leni [432]

Answer:

$71. \ \ \ f(a) \ = \ 7a \ - \ 3; \ f(a+h) \ = \ 7a \ + \ 7h \ - \ 3; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 7$

$72. \ \ \ f(a) \ = \ 5a^{2}; \ f(a+h) \ = \ {5a}^{2} \ + \ 10ah \ + \ {5h}^{2}; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 10a \ + \ 5h$

Step-by-step explanation:

In single-variable calculus, the difference quotient is the expression

$\displaystyle\frac{f(x+h) \ - \ f(x)}{h}$ ,

which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).

This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.

$m \ \ = \ \ \displaystyle\frac{\Delta y}{\Delta x} \ \ = \ \ \displaystyle\frac{rise}{run}$ .

Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as h approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.

Therefore,

$71. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{(7a \ + \ 7h \ - \ 3) \ - \ (7a \ - \ 3)}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{7h}{h} \\ \\ \-\hspace{4.25cm} = \ \ 7$

$72. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{{5(a \ + \ h)}^{2} \ - \ {5(a)}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{{5a}^{2} \ + \ 10ah \ + \ {5h}^{2} \ - \ {5a}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{h(10a \ + \ 5h)}{h} \\ \\ \-\hspace{4.25cm} = \ \ 10a \ + \ 5h$