Answer:6.6666666667
Step-by-step explanation:just divided it
Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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For this case we have the following expression:
-9x ^ -1y ^ -1 / -15x ^ 5 y ^ -3
For power properties we have:
-9x ^ (- 1-5) y ^ (- 1 - (- 3)) / - 15
Rewriting we have:
9x ^ (- 6) y ^ (- 1 + 3) / 15
3x ^ (- 6) y ^ (2) / 5
3y ^ 2 / 5x ^ 6
Answer:
3y ^ 2 / 5x ^ 6Note: answer is not between the options. Rewrite the expression again, or the options.
Answer:
fourth picture
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
The gradient is the ratio of the change in y to the change in x:
m = ∆y/∆x = (16 -6)/(2 -0) = 10/2 = 5
The gradient of the line segment is 5.