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3 years ago

67. Find all points on the x-axis that are 5 units from the point (4, -3).

Mathematics

1 answer:

Setler [38]3 years ago

5 0

Answer:(9,2) I assume I don’t really understand the question

Step-by-step explanation:

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Please solve AND give a STEP BY STEP SOLUTION

RUDIKE [14]

2(-n - 3) -7(5+2n)
-2n - 6 - 35 - 14n
-16n - 41
B. -16 - 41

3 0

3 years ago

If a laptop computer regularly costs $979 and is on sale for $679, what percentage discount is being given? Round your answer to

Lady_Fox [76]

Answer:

Look at the attachment

4 0

3 years ago

Read 2 more answers

Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab

Nastasia [14]

Answer:

1/12

Step-by-step explanation:

Needed information

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

The sum of the probabilities of all outcomes must equal 1

Solution

We are told that the probability that the counter is not black is 3/4.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is black by subtracting 3/4 from 1:

$\sf P(counter\:not\:black)=\dfrac34$

$\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14$

We are told that the probability that the counter is not white is 2/3.

As the sum of the probabilities of all outcomes must equal 1, we can work out the probability that the counter is white by subtracting 2/3 from 1:

$\sf P(counter\:not\:white)=\dfrac23$

$\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13$

We are told that there are black, white and grey counters in the bag. We also know that the sum of the probabilities of all outcomes must equal 1. Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

$\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}$

7 0

2 years ago

Please help me with this question!

Rasek [7]

Answer:

87 packages

Step-by-step explanation:

First we need to find the volume of the cone-shaped vase.

The volume of a cone is given by:

V_cone = (1/3) * pi * radius^2 * height

With a radius of 9 cm and a height of 28 cm, we have:

V_cone = (1/3) * pi * 9^2 * 28 = 2375.044 cm3

Each package of sand is a cube with side length of 3 cm, so its volume is:

V_cube = 3^3 = 27 cm3

Now, to know how many packages the artist can use without making the vase overflow, we just need to divide the volume of the cone by the volume of the cube:

V_cone / V_cube = 2375.044 / 27 = 87.9646 packages

So we can use 87 packages (if we use 88 cubes, the vase would overflow)

5 0

3 years ago

Read 2 more answers

The Miller family visited Mama's Kitchen and ordered 4 hamburgers and 3 medium fries and paid $18.69. James ordered a medium dri

sergij07 [2.7K]

To answer the question, let x be the cost of each hamburger, y be the cost of each medium fries, and z be the cost of each medium drink. The equations that are described in the problem are,
(Miller ) 4x + 3y = 18.69
(James) x + 2y + z = 8.66
(Steven) 2x + y + z = 10.27
Solving simultaneously for the values of the variables give x = 3.36, y = 1.75, and z = 1.8.
Thus, each hamburger costs $3.36. Each medium fries cost $1.75, and each drink costs $1.8.

3 0

3 years ago