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Helen [10]
3 years ago
11

Jack is selling holiday ornaments and boxes of candy. Each ornament is $1.50 and

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

x = 12, y =

Step-by-step explanation:

Let x=# of Ornaments and y=# of boxes of candy.  The system of equations is:

x + y = 15

1.5x + 3y = 27

And solve via elimination

1.5 x = 18

x = 12, y =3

HAVE A GOOD DAY

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What point divides the line segment between (10,-2) and (-6,6) into a ratio of 5:3
olganol [36]

Answer: (0,3)

Step-by-step explanation:

You follow the formulas to find the x and y of the dividing points.

Xp= x1+ a/a+b (x2-x1)

Xp= 10+5/5+3(-6-10)

Xp=10+5/8(-16)

Solve the problem above and you end up with “0” as your x.

Yp= y1+ a/a+b (y2-y1)

Yp= -2+ 5/8 (6+2)

Yp= -2+ 5/8 (8)

Solve this problem above and you end up with “3” as your y. Therefore, the point that divides the line segment between (10, -2) and (-6,6) into a ratio of 5:3 is (0, 3).

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3 years ago
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Step-by-step explanation:

a vector multiplied by a scalar is equal to it's image. The expression above gives an equation and after solving, it gives you the image

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(25÷8)×219078%+2347910.Please show working on paper.Thanks.You will get 10 points.PLEASE HELP..
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Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

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Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

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