Answer:
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Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer:
1) 16
2) 12
4) 4
5) 0
Step-by-step explanation:
Plug in the value for x in the equation above and solve for y for all 5.
Answer:
Step-by-step explanation:
4x + 7 + 2x + 5 = 180
6x + 12 = 180
6x = 168
x = 28
4(28) + 7= 112 + 7= 119
2(28) + 5 = 56 + 5= 61
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