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timama [110]
3 years ago
7

In the adjoining parallelogram ABCD, A is joined to any point E on BC. AE and DC produced meet at E Prove that. area of ∆BEF = a

rea of ∆ CDE​
Mathematics
2 answers:
baherus [9]3 years ago
5 0
Wow vvvvvvvvvvvvvvbbbbbb
Tanzania [10]3 years ago
4 0

Answer:

<h3>In parallelogram ABCD any point E is taken on the side BC . AE and DC when produced to meet at a point M . Prove that ar(ADM) = ar(ABMC) .</h3>

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Answer:

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Step-by-step explanation:

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4 years ago
Which statements about experimental probability are true? Check all that apply.
makvit [3.9K]
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6 0
3 years ago
Read 2 more answers
Evaluate the expression for x=5, y=-3 and z=7<br> (x2 – z) (22+5)
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(Refer to image)

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I need help with this ​
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Step-by-step explanation:

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3 years ago
Given a quadratic function in vertex form:
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See below

Step-by-step explanation:

<u>Part A</u>

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<u>Part B</u>

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<u>Part C</u>

A vertical stretch is different than a horizontal compression:

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<u>Part D</u>

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7 0
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