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forsale [732]
3 years ago
6

Calculate the mass of water produced when 9.57 g of butane reacts with excess oxygen.

Chemistry
1 answer:
irinina [24]3 years ago
4 0

Answer:

14.9 g

Explanation:

Step 1: Write the balanced equation

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 9.57 g of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

9.57 g × 1 mol/58.12 g = 0.165 mol

Step 3: Calculate the moles of H₂O produced from 0.165 moles of C₄H₁₀

0.165 mol C₄H₁₀ × 5 mol H₂O/1 mol C₄H₁₀ = 0.825 mol H₂O

Step 4: Calculate the mass corresponding to 0.825 mol of H₂O

The molar mass of H₂O is 18.02 g/mol.

0.825 mol × 18.02 g/mol = 14.9 g

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The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.

The given parameters;

  • <em>mass of the sodium chloride, = 14.5 g</em>
  • <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>

<em />

In the reaction above, we can deduce the following;

molecular mass of 2Nacl = 2(58.44) = 116.88 g

molecular mass of 2NaF = 2(42) = 84 g

molecular mass of  Cl2 = 71 g

The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 84 g of NaF

14.5 g of NaCl -------------------  ?

= \frac{84 \times 14.5}{116.88} \\\\= 10.42 \ g

The mass of  chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;

116.88 g of NaCl --------------- 71 g of Cl2

14.5 g of NaCl ------------------- ?

= \frac{14.5 \times 71}{116.88} \\\\= 8.81 \ g

Learn more here:brainly.com/question/8470145

8 0
3 years ago
Which macro nutrient is made up of carbon and hydrogen elements join together in long groups called hydrocarbons?
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What volume of 1.5M NaOH is needed to provide 0.75 mol of NaOH?
lutik1710 [3]
1.5M NaOH so we've 1.5 moles of NaOH in 1L of solution

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1.5 moles of NaOH ------------in------------- 1000 ml
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x = 500 ml

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