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Shtirlitz [24]
2 years ago
7

Calculate the number of moles of KOH in 6.70 mL of a 0.480 M KOH solution. (Enter your answer in scientific notation.)

Chemistry
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

3.2×10^-3 mol

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

The question gives you the volume in mL, so to convert "mL" to "L" you need to divide by 1000. (6.70mL/ 1000L)= 0.0067L.

Now you can plug the numbers into the equation. 0.480M= n/ 0.0067L), multiply (0.480M×0.0067L)= 0.003216 mol. The scientific notation is 3.2×10^-3, 10^-3 because you move the decimal back three times and 3.2 because there are 2 sig figs.

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Answer:

D

Explanation:

The greater the distance apart, the lesser the gravitational force between the objects

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3 years ago
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Particle size directly affects which of the following spil properties?
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Answer:

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3 years ago
An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:
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Answer:

2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Explanation:

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Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

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8 0
3 years ago
4 NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
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Answer:

0.9 moles of water

Explanation:

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5 : 6

divide by 5 on both sides

1 : 1.2

multiply by 0.75 on both sides

0.75 : 0.9

So the result is 0.9 moles of water

(Please correct me if I'm wrong)

5 0
2 years ago
Trans fats: Think about how the prefix trans- is used in naming alkenes.
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-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
4 0
3 years ago
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